原式=x-x÷{(x+y)(x-y) / (x+y)(x²-xy+y²) [(xy-x²-y²) / y × xy / (y-x)]}
=x-x÷{(x-y) / (x²-xy+y²) × [-(x²-xy+y²)] / y × xy / [-(x-y)]
=x-x÷x
=x-1
原式=x-x÷{(x+y)(x-y) / (x+y)(x²-xy+y²) [(xy-x²-y²) / y × xy / (y-x)]}
=x-x÷{(x-y) / (x²-xy+y²) × [-(x²-xy+y²)] / y × xy / [-(x-y)]
=x-x÷x
=x-1