Question

因式分解：4a的平方bc-3a的平方c的平方+8abc-6ac的平方

Answer 1

a²+2ab_b8-a-b

=(a+b)²-(a+b)

=(a+b)(a+b-1)

(m²+3m)²-8(m²+3m)-20

=(m²+3m-10)(m²+3m+2)

=(m+5)(m-2)(m+1)(m+2)

(x²-x)/(x+1)*(x²-1)/(x²-2x+1)

=x(x-1)/(x+1)*(x+1)(x-1)/(x-1)²

=x/(x-1)

因为x²-3x+2=0

所以(x-1)(x-2)=0

x=1或x=2

x=1时,原式无意义所以x=2

所以

原式=2/(2-1)=2