sin2π/5=sin72
cos5π/6= cos75=sin15 < sin72,
故sin2π/5 >cos5π/6
tan7π/5=tan(7π/5 -π)=tan2π/5=(sin2π/5) / (cos2π/5),
而 0< cos2π/5 sin2π/5
所以
tan7π/5 > sin2π/5 >cos5π/6
sin2π/5=sin72
cos5π/6= cos75=sin15 < sin72,
故sin2π/5 >cos5π/6
tan7π/5=tan(7π/5 -π)=tan2π/5=(sin2π/5) / (cos2π/5),
而 0< cos2π/5 sin2π/5
所以
tan7π/5 > sin2π/5 >cos5π/6