(1+cos2a)/(tana/2)-(cota/2)=(1+cos2a)*(cota/2)-(cota/2)=cos2acota/2是不是打错了(1+cos2A)/[tan(A/2)-cot(A/2)]=2cosA^2/[sin(A/2)/cos(A/2)-cos(A/2)/sin(A/2)]=2cosA^2*sin(A/2)*cos(A/2)/[sin(A/2)^2-cos(A/2...
化简(1+cos2a)/(tana/2)-(cota/2)
1个回答
相关问题
-
化简(1+cos2a)/(tana/2-cota/2)
-
sin^2 a*tana+cos^2*cota+2sina*cosa,化简
-
化简:tana·cota-sina·cos(3π/2+a)=
-
化简:(2tana+3cota)^2-(2tana-3cota)^2=
-
化简 cos2a/(1-2tana*cos^2a)
-
化简 cos2a/(1-2tana*cos^2a)
-
化简(sina)^2*tana 2sina*cosa (cosa)^2*cota
-
cos^2a+cota(-tana)
-
tanA=1/ tanA=sinA/ cotA=cosA/ sin^2A+cos^2A=
-
(sin2a+cos2a+1)/(1+tana)化简