Question

(X2-X)2+(X2+3X+2)2-4(X2+X+1)2因式分解

Answer 1

(X2-X)2+(X2+3X+2)2-4(X2+X+1)2

解原式=(x²-x-2x²-2x-2)(x²-x+2x²+2x+2)+(x²+3x+2)²

=(-x²-3x-2)(3x²+x+2)+(x²+3x+2)²

=(x²+3x+2)(-3x²-x-2+x²+3x+2)

=(x+1)(x+2)(-2x²+2x)

=-2x(x+1)(x+2)(x-1)

楼上的根本就不懂