设1/[(t+1)²(t-2)]=A/(t+1) + B/(t+1)² + C/(t-2)
右边合并后与左边比较系数得:A=-1/9,B=-1/3,C=1/9
∫ 1/[(t+1)²(t-2)] dt
=-(1/9)∫ 1/(t+1) dt - (1/3)∫ 1/(t+1)² dt + (1/9)∫ 1/(t-2) dt
=-(1/9)ln|t+1| + (1/3)/(t+1) + (1/9)ln|t-2| + C
希望可以帮到你,如果解决了问题,请点下面的"选为满意回答"按钮,
设1/[(t+1)²(t-2)]=A/(t+1) + B/(t+1)² + C/(t-2)
右边合并后与左边比较系数得:A=-1/9,B=-1/3,C=1/9
∫ 1/[(t+1)²(t-2)] dt
=-(1/9)∫ 1/(t+1) dt - (1/3)∫ 1/(t+1)² dt + (1/9)∫ 1/(t-2) dt
=-(1/9)ln|t+1| + (1/3)/(t+1) + (1/9)ln|t-2| + C
希望可以帮到你,如果解决了问题,请点下面的"选为满意回答"按钮,