已知,二次函数y=ax2-2x+c的图象与X轴交于A,B两点(点A 在点B的左侧),与Y轴交于点C对称轴是过点(1,0)

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  • (1) 对称轴过点(1,0),方程为x = 1= -(-2)/(2a) = 1/a,a = 1

    y = x^2 -2x +c = (x-1)^2 + c-1

    图象向右平移一个单位后,二次函数方程为y = (x-1 -1)^2 + c -1 = (x-2)^2 + c - 1

    经过坐标原点O:0 = (0-2)^2 + c -1,c = -3

    二次函数为y = x^2 -2x -3

    (2)D(0,1),B(3,0),DB斜率:-1/3

    C(0,-3),BC斜率:1

    E(1,-4),BE斜率:2

    tgA = |[(-1/3 -1)/[1+(-1/3)*1]| = 2

    tgB = |(2 -1)/(1+2*1)| = 1/3

    tg(A - B) = (tgA - tgB)/(1 + tgAtgB) = (2 - 1/3)/(1 + 2*1/3) = 1

    A - B = 45度

    (3) P(1,a)

    PA^2 = PC^2

    (1+1)^2 + (a-0)^2 = (1-0)^2 + (a +3)^2

    a = -1

    P(1,-1)

    PA^2 = 4+1 = 5

    DB = √[(3-0)^2 + (0 -1)^2] = √10

    三角形BDM的面积的值等于PA平方:

    5 = (1/2)*DB*DB上的高

    = DB上的高 * √10/2

    DB上的高(M与BD的距离) = 10/√10 = √10

    设M的坐标为(m,m^2 -2m -3),m>0

    DB的方程为:y=-1/3x+1,改写为 x + 3y -3 =0

    M与BD的距离:|m +3(m^2 -2m -3)|/√(1+3^2) = √10

    |3m^2 -5m -12| = 10

    3m^2 -5m -12 >= 0时:3m^2 -5m -12 = 10

    3m^2 -5m -22 = 0

    m = -2 (= 0)

    3m^2 -5m -12<0时:3m^2 -5m -12 = -10

    3m^2 -5m -2 = 0

    m = -1/3 (