Question

解方程(1)1/x+1 +3/2-x=0 (2)12/1-9x^2-3x+1/3x-1=1-3x/1+3x

Answer 1

(1)

1/x+1 +3/2-x=0

1/x+1 =3/(x-2)

x-2=3(x+1)

2x=-5

x=-5/2

(2)

12/(1-9x^2)-(3x+1)/(3x-1)=(1-3x)/(1+3x)

12+(3x+1)^2-(1-3x)^2=0

12+12x=0

x=-1