(1)当t=-1时,lg(x+1)≤lg(2x-1)^2,x+1≤(2x-1)^2,得:x≤0或x≥5/4
(2)lg(x+1)≤lg(2x+t)^2,(x+1)≤(2x+t)^2
4x^2+(4t-1)x+t^2-1≥0恒成立..分三种情况讨论,就是对称轴在[0,1]左右内.这里写不下.
(1)当t=-1时,lg(x+1)≤lg(2x-1)^2,x+1≤(2x-1)^2,得:x≤0或x≥5/4
(2)lg(x+1)≤lg(2x+t)^2,(x+1)≤(2x+t)^2
4x^2+(4t-1)x+t^2-1≥0恒成立..分三种情况讨论,就是对称轴在[0,1]左右内.这里写不下.