Question

(3根号2-根号3)(根号3+根号2)负1/6的次方

Answer 1

(3√2-√3)( √3+√2)^-1/6

=(3√2-√3)×[1/( √3+√2) ^1/6]

=(3√2-√3)×[ ( √3+√2) ^5/6/( √3+√2) ^5/6( √3+√2) ^1/6]

=(3√2-√3)×( √3+√2) ^5/6/( √3+√2) ^5/6+1/6

=(3√2-√3)×( √3+√2) ^5/6/( √3+√2)

=[(3√2-√3)×(√3-√2) ( √3+√2) ^5/6]/[( √3+√2) (√3-√2) ]

=(4√6-9) ( √3+√2) ^5/6/ (3-2)

=(4√6-9) ( √3+√2) ^5/6

1年前

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