(x+y)(x²-xy+y²)—xy(x+y)因式分解
3个回答
(x+y)(x²-xy+y²)—xy(x+y)
=(x+y)(x²-xy+y²-xy)
=(x+y)(x²-2xy+y²)
=(x+y)(x-y)²
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因式分解:(x+y)(x+y+2xy)+(xy+1)(xy-1)=______.
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