已知实数x,y满足x2+5y2+4xy+y+1/4=0,求x,y.
2个回答
配方:
(x+2y)^2+ (y+1/2)^2= 0
所以:
x+2y=0,y+1/2=0
解得:
x=1,y=-1/2
相关问题
已知实数x,y满足x2+y2-xy+x-1/2y+1/4=0 试求x,y的值
已知实数x,y满足5x²+2y²+1=6xy+4x-2y,则x²-xy+2000y
已知实数x,y满足5x^2-3xy+1\2y^2-2x+1\2y+1\4=0,求x,y的值
已知实数x.y满足x^2+y^2-4x-5=0,求:
已知实数x、y满足|2x-y+1|+2(3x-2y+4)2=0,求代数式1−x−yx−2y÷x2−y2x2−4xy+4y
已知实数x、y满足x^2+4xy+4y^2+x+2y-6=0,求x+2y的平方根是多少?
实数x y满足x≥y≥1和2x²-xy-5x+y+4=0求x+y之值
已知实数x,y满足x2+y2+2x-4y+5=0
实数x、y满足x≥y≥1和2x^2-xy+5x-y+4=0,则x+y=___
实数x,y满足x≥y≥1和2x2-xy-5x+y+4=0,则x+y=______.