Question

用C语言编,有两个正整数a和b,已知a*b=2048,求a,b各为何值时,a+b的值最小

Answer 1

#include

#include

main()

{

int a=0,b=0,min=2048,num_a,num_b;

for (a = 1; a a+b)

{

min = a + b;

num_a=a;

num_b=b;

}

}

}

printf("%d %dn",num_a,num_b);

}

答案是32和64.