Question

有若干个数,a1、a2、a3...an,若a=-1/2,从第二个数起,每个数都等于“1与它前面的那个数的差的倒数”

Answer 1

1.

a(2)=2/3

a(3)=3

2.

a(4)=a(1)

a(k)=a(k+3n)

a(9)=a(3)=3;a(10)=-1/2;a(11)=2/3;

3.

M=a1*(an(1-a(n))+1)=(a(n)/a(n+1)+1)*a1=-1/8或-11/18或-5/12