Question

解方程组x^2-(9/4)y^2=0 (4/3) x^2+4xy+3y^2=1/3过程.

Answer 1

x^2-(9/4)y^2=0

x^2=(9/4)y^2

y=2x/3或y=-2x/3

y=2x/3

(4/3) x^2+4xy+3y^2=1/3

4/3*x^2+8/3*x^2+4/3*x^2=1/3

16/3*x^2=1/3

x^2=1/16

x=±4

y=2x/3

y=-2x/3

(4/3) x^2+4xy+3y^2=1/3

4/3*x^2-8/3*x^2+4/3*x^2=1/3

0=1/3

不成立

所以

x=4,y=8/3

x=-4,y=-8/3