Question

线性代数:如何把 1 2 3 4 3 5 7 9 2 3 4 5 化成行化简阶梯矩

Answer 1

A =

1 2 3 4

3 5 7 9

2 3 4 5

A =

1 2 3 4

0 -1 -2 -3

0 -1 -2 -3

A =

1 2 3 4

0 -1 -2 -3

0 0 0 0

A =

1 0 -1 -2

0 -1 -2 -3

0 0 0 0