Question

已知绝对值x-4+(y-9)^2=0试求(y-x/y+x)^2的值

Answer 1

∣x-4∣+(y-9)^2=0

因为∣x-4∣>=0,(y-9)^2>=0

所以x-4=0,y-9=0

x=4

y=9

[(y-x)/(y+x)]^2

=[(9-4)/(9+4)]^2

=(5/13)^2

=25/169