Question

若X-Y+2的绝对值与X+Y-1开算数平方根护卫相反数,求22X+2Y开立方根的值.

Answer 1

由题意得：|X-Y+2|=-√(X+Y-1)

即：|X-Y+2|+√(X+Y-1)=0

∴|X-Y+2|=0

且√(X+Y-1)=0

即：

X-Y+2=0

X+Y-1=0

解得：

X=-1/2

Y=3/2

则22X+2Y=22×(-1/2)+2×(3/2)=-11+3=-8

∴立方下(22X+2Y)=立方下(-8)=-2