Question

由曲线y=x²+1,直线y=4x-3以及x轴,y轴围成的区域面积为多少

Answer 1

先算交点:

y=x^2

y=4x-3

x^2=4x-3

x^2-4x+3=0

x=3 or x=1

面积=|∫[x^2-(4x-3)]dx | (1,3)

=|1/3x^3-2x^2+3x| (1,3)

=4/3