Question

1吨水中加入10千克NAOH,其PH值为多少

Answer 1

NaOH的物质的量 = 10000/40 = 250 mol,溶液体积 = 1000 L,物质的量浓度 = 250/1000 = 0.25 mol/L,H+浓度[H+] = 10^(-14) / 0.25 = 4 * 10^(-14),pH = - lg[H+] = - lg [ 4*10^(-14)] = 13.40,即溶液的pH = 13.40.别...