1﹚2x²-6x+7=2﹙x²-3x+7/2﹚
=2[x²-3x+﹙3/2﹚²-﹙3/2﹚²+7/2]
=2﹙x-3/2﹚²+5/2≥5/2
∴2x²-6x+7>0
2﹚ 2x²+x-3=2﹙x²+1/2 x-3/2﹚
=2﹙x+1/4﹚²-25/8≥﹣25/8
1﹚2x²-6x+7=2﹙x²-3x+7/2﹚
=2[x²-3x+﹙3/2﹚²-﹙3/2﹚²+7/2]
=2﹙x-3/2﹚²+5/2≥5/2
∴2x²-6x+7>0
2﹚ 2x²+x-3=2﹙x²+1/2 x-3/2﹚
=2﹙x+1/4﹚²-25/8≥﹣25/8