Question

二次根式化简(a/(a+2b))根号下((a^2b^2+4ab^2+4b^2)/a) (a>0,b>0)

Answer 1

=√((（a^2b^2+4ab^2）+4b^2)/a^2)*(a^2/(a+b)^2))

=√(ab+b)^2/(a+2b)^2

=(ab+b)/(a+2b)