设数列{an}和{bn}的前n项和分别为Sn,Tn,且Sn/Tn=7n+2/n+3,则a8/b8等于多少?
1个回答
应该是等差数列吧
S15=(a1+a15)*15/2
a1+a15=2a8
所以S15=15a8
同理T15=15b8
所以a8/b8=S15/T15
=(7×15+2)/(15+3)
=107/18
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