Question

已知直线l上两点A(-2,3),B(3,-2),求其斜率,若点C(a,b)在直线L上,求a,b间应满足的关系,并求当a=

Answer 1

斜率=(-2-3)/(3+2)=-1

L方程为：(y-3)/(x+2)=(y+2)/(x-3)

整理得：y=-x+1

∵C(a,b)在L上,

∴b=-a+1=1-a

当a=1/2时,b=1-1/2=1/2