Question

已知室温时,0.1mol/L某一元酸HA在水中有0.1%发生电离,求此酸的电离平衡常数

Answer 1

HA ===可逆=== H+ + A-

0.1*(1-0.1%) 0.1*0.1% 0.1*0.1%

K===c(H+)*c(A-)/c(HA)==0.10.1%*0.10.1%/[0.1(1-0.1%)]==0.1%*0.1%/0.1===1×10^-7