速求50道初一上学期代数式化简题!

1个回答

  • -2n-(3n-1) a-(5a-3b)+(2b-a) -3(2s-5)+6s 1-(2a-1)-(3a+3) 3(-ab+2a)-(3a-b) 14(abc-2a)+3(6a-2abc) 3(xy-2z)+(-xy+3z) -4(pq+pr)+(4pq+pr)

    1.-2n-(3n-1)

    原式=-2n-3n+1

    =-5n+1

    2.a-(5a-3b)+(2b-a)

    原式=a-5a+3b+2b-a

    =-5a+5b

    3.-3(2s-5)+6s

    原式=-6s+15+6s

    =15

    4.1-(2a-1)-(3a+3)

    原式=1-2a+1-3a-3

    =-1-5a

    5.3(-ab+2a)-(3a-b)

    原式=(-3ab+6a)-3a+b

    =-3ab+6a-3a+b

    =-3ab+3a+b

    6.14(abc-2a)+3(6a-2abc)

    原式=14 abc-28a+(18a-6abc)

    =14abc-28a+18a-6abc

    =8abc-10a

    7.3(xy-2z)+(-xy+3z)

    解 原式=3xy-6z-xy+3z

    =2xy-3z

    8.-4(pq+pr)+(4pq+pr)

    原式=-(4pq+4pr)+4pq+pr

    =-4pq-4pr+4pq+4pr

    3ab-4ab+8ab-7ab+ab=______. 7x-(5x-5y)-y=______. 23a3bc2-15ab2c+8abc-24a3bc2-8abc=______. -7x2+6x+13x2-4x-5x2=______. 2y+(-2y+5)-(3y+2)=______. (2x2-3xy+4y2)+(x2+2xy-3y2)=______. 2a-(3a-2b+2)+(3a-4b-1)=______. -6x2-7x2+15x2-2x2=______. 2x-(x+3y)-(-x-y)-(x-y)=______. 2x+2y-[3x-2(x-y)]=______. 5-(1-x)-1-(x-1)=______. (4xy2-2x2y)-( )=x3-2x2y+4xy2+y3. 已知A=x3-2x2+x-4,B=2x3-5x+3,计算A+B=______. 已知A=x3-2x2+x-4,B=2x3-5x+3,计算A-B=______. 若a=-0.2,b=0.5,代数式-(|a2b|-|ab2|)的值为______.

    3.3ab-4ab+8ab-7ab+ab=______.

    4.7x-(5x-5y)-y=______.

    5.23a3bc2-15ab2c+8abc-24a3bc2-8abc=______.

    6.-7x2+6x+13x2-4x-5x2=______.

    7.2y+(-2y+5)-(3y+2)=______.

    11.(2x2-3xy+4y2)+(x2+2xy-3y2)=______.

    12.2a-(3a-2b+2)+(3a-4b-1)=______.

    13.-6x2-7x2+15x2-2x2=______.

    14.2x-(x+3y)-(-x-y)-(x-y)=______.

    16.2x+2y-[3x-2(x-y)]=______.

    17.5-(1-x)-1-(x-1)=______.

    18.( )+(4xy+7x2-y2)=10x2-xy.

    19.(4xy2-2x2y)-( )=x3-2x2y+4xy2+y3.

    21.已知A=x3-2x2+x-4,B=2x3-5x+3,计算A+B=______.

    22.已知A=x3-2x2+x-4,B=2x3-5x+3,计算A-B=______.

    23.若a=-0.2,b=0.5,代数式-(|a2b|-|ab2|)的值为______.

    25.一个多项式减去3m4-m3-2m+5得-2m4-3m3-2m2-1,那么这个多项式等于______.

    26.-(2x2-y2)-[2y2-(x2+2xy)]=______.

    27.若-3a3b2与5ax-1by+2是同类项,则x=______,y=______.

    28.(-y+6+3y4-y3)-(2y2-3y3+y4-7)=______.

    29.化简代数式4x2-[7x2-5x-3(1-2x+x2)]的结果是______.

    30.2a-b2+c-d3=2a+( )-d3=2a-d3-( )=c-( ).