二次根式的乘除(二)初三开学刚教高手进

1个回答

  • 1.t/(t+1)-(t^2-1)/[(t+2)^2-1]乘以(t+3)/(t+1)

    =t/(t+1)-(t+1)(t-1)/(t+2+1)(t+2-1)乘以t+3)/(t+1)

    =t/(t+1)-1

    =(t-t-1)/(t+1)

    =-1/(t+1)

    2.-(√-m^3)-[m√(-1/m)]

    =-√-m(m^2)-√m^2(-1/m)

    =-m√-m-√-m

    =(-m-1)(-√-m)

    =(m+1)√-m

    (和您的结果完全一致)!