∵(x+1)²+|y-2|=0
∴x+1=0
y-2=0
∴x=-1
y=2
∴x²y²+3xy-7x²y²-(5/2)xy+1+5x²y²
=-x²y²+(1/2)xy+1
=-(-1)²×2²+(1/2)×(-1)×2+1
=-4-1+1
=-4
∵(x+1)²+|y-2|=0
∴x+1=0
y-2=0
∴x=-1
y=2
∴x²y²+3xy-7x²y²-(5/2)xy+1+5x²y²
=-x²y²+(1/2)xy+1
=-(-1)²×2²+(1/2)×(-1)×2+1
=-4-1+1
=-4