是从11²+12²+.58²
根据1²+2²+3²+...n²=n(n+1)(2n+1)/6
11²+12²+.58²=(1²+2²+3²+...58²)-(1²+2²+3²+...10²)
=58*59*117/6-10*11*21/6
=66729-385
=66344
是从11²+12²+.58²
根据1²+2²+3²+...n²=n(n+1)(2n+1)/6
11²+12²+.58²=(1²+2²+3²+...58²)-(1²+2²+3²+...10²)
=58*59*117/6-10*11*21/6
=66729-385
=66344