Question

一道数学题：如果x³-（2-bx）+3是三次二项式,求a²-b的2010次方的值

Answer 1

= x^3 - 2 +bx +3 = x^3 + bx +1

=> b =0

a^2 -b = a^2 - 0 = 1

1^2010 = 1