已知函数f(x)=2√3sin(x/2+π)cos

2个回答

化简f(x),g(x)=f(x-π/6),再判断g(x)在区间[0,g(x)在区间[0,π]上的最大值和最小值.
或直接化简g(x)=f(x-π/6),再判断g(x)在区间[0,g(x)在区间[0,π]上的最大值和最小值.

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