应该是an=1/2a(n-1)+1吧
an-2=1/2(a(n-1)-2)
bn=1/2b(n-1)因此bn等比
b1=-1
bn=-(1/2)^(n-1)
an=bn+2=-(1/2)^(n-1)+2
数列｛an｝满足a1=1,an=1/2a(n-1)1(n≥2)
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