Question

将分式10X^2+30X+20/X^3+2X^2－X－2 约分,再将使分试值为正整数时,求整数X的值?

Answer 1

(10X^2+30X+20)/(X^3+2X^2－X－2) =10(X+2)(X+1)/[X^2*(X+2)-(X+2)] =10(X+2)(X+1)/[(X-1)(X+1)(X+2)] =10/(X-1) 若分数值为正整数值,则X=2或X=3或X=6或X=11