Question

使代数式x+2/x-3除以x+1/x-2有意义的x满足

Answer 1

(x+2)/(x-3)除以(x+1)/(x-2)

=(x+2)/(x-3)*[(x-2)/(x+1)]

=(x+2)(x-2)/[(x-3)(x+1)]

使得代数式有意义的x满足：

x-3≠0且x-2≠0且x+1≠0

即：x≠3且x≠2且x≠-1