a²+b²+c²-ab-bc-ac
=1/2(2a²+2b²+2c¹-2ab-2bc-2ac)
=1/2[﹙a-b﹚²+﹙b-c﹚²+﹙a-c﹚²]
=1/2[﹙x/20+20-x/20-19﹚²+﹙x/20+19-x/20-21﹚²+﹙x/20+20-x/20-21﹚²]
=1/2[﹙20-19﹚²+﹙19-21﹚²+﹙20-21﹚²]
=1/2[1+4+1]
=﹙1/2﹚*6
=3
选A.3
a²+b²+c²-ab-bc-ac
=1/2(2a²+2b²+2c¹-2ab-2bc-2ac)
=1/2[﹙a-b﹚²+﹙b-c﹚²+﹙a-c﹚²]
=1/2[﹙x/20+20-x/20-19﹚²+﹙x/20+19-x/20-21﹚²+﹙x/20+20-x/20-21﹚²]
=1/2[﹙20-19﹚²+﹙19-21﹚²+﹙20-21﹚²]
=1/2[1+4+1]
=﹙1/2﹚*6
=3
选A.3