Question

求函数y=1/x在x=2处的切线方程

Answer 1

y'=-1/x^2 x=2k=y'=-1/4

x=2,y=1/2 切点 (2,1/2)

y-1/2=1/4(x-2)

y-1/2=1/4x-1/2

切线方程y=1/4x