Question

已知函数f(x)=ax5-bx3+cx-3,f(-3)=7,则f(3)的值是什么?

Answer 1

f(x)=ax5-bx3+cx-3

f(3)=a*(-3)^5+b*(-3）^3-c*(-3)-3=7

所以a*(-3)^5+b*(-3）^3-c*(-3)=10

f(3)=a*3^5+b*3^3-c*3-3

=-[-a*(-3)^5+b*(-3）^3-c*(-3)]-3

=-10-3

=-13