x2(y2-1)-(y2-1),把y2-1提取,就成=(y2-1)(x2-1）
X2y2-x2-y2+1 =x2(y2-1)-(y2-1) =(y2-1)(x2-1) =(y+1)(y-1)(x+1)
1个回答
相关问题
-
已知X1^2+X2^2,X1+X2,Y1^2+Y2^2,Y1+Y2,X1Y1+X2Y2求X2Y1-X1Y2
-
(y-y1)/(y2-y1)=(x-x1)/(x2-x1)与(y-y1)/(x-x1)=(y2-y1)/(x2-x1)的
-
Y=1-根号（1-x^2） 1-x^2=(1-y)^2 x^2=1-(1-y)^2 x^2=2y-y^2 因为：-1≤x
-
数学公式推导max{|x1-x2|,|y1-y2|} =（|x1+y1-x2-y2|+|x1-y1-(x2-y2)|）/
-
=[y^2*x+x-y-x^2*y]/[(x^2+1)(y^2+1)] =[(x-y)+xy(y-x)}/[(x^2+1
-
（1）2x2x−1-x-1（2）（[x/x−y]-[2y/x−y]）•[xy/x−2y]÷（[1/x]+[1/y]）（3
-
请问y - y1 = (y2-y1) / (x2-x1) * (x-x1) 怎么变成 (y-y1) / (y2-y1)
-
已知向量a=(x1,y1),向量b=(x2,y2),求证(x1x2+y1y2)^2≤(x1^2+y1^2)(x2^2+y
-
x1,y1属于R,x1^2+y1^2=9,x2^2+y2^2=16.证明(x1x2+y1y2)^2
-
y3-y2-y+1/y2-1 × x2-1/x3-x2-x+1 × x-1/y-1