Question

已知（2ab^m）^3/28a^nb^4=2\7b^2,求m,n的值

Answer 1

（2ab^m）^3/28a^nb^4=27b^2

8a^3*b^(3m)/(28a^n*b^4)=2/(7b^2)

a^3*b^(3m)/(a^n*b^4)=1/b^2

a^3*b^(3m+2)=a^n*b^4.

=>n=3,3m+2=4.

即：m=2/3,n=3.