(2又5/9+3又9/10-5.22)/(2又5/9-6又27/50+5.22)÷（ （2006×0.4/2008×0.5）+1.6/2008 】
=(23/9+39/10-522/100)/(23/9-327/50+522/100)÷{[(2006x(2/5)/2008x(1/2)]+16/20080}
=(23/9-132/100)/(23/9-132/100)÷{[(4012/5)/2008x(1/2)]+16/20080}
=1÷{[(4012/10040x(1/2)]+16/20080}