Question

数学分式通分与约分约分 (x²+xy)/(x+y)² x²-y²/（x²-y²）通分2xy/(x+y)²与x/x²-y²

Answer 1

约分

(x²+xy)/(x+y)²

=x(x+y)/(x+y)²

=x/(x+y）

x²-y²/（x²-y²）=1

通分

2xy/(x+y)²与x/x²-y²

2xy/(x+y)²=2xy(x-y)/[(x+y)²（x-y）]

x/(x²-y²)=x(x+y)/[(x+y)²(x-y)]

x-y/2x+2y与xy/(x+y)²

(x-y)/(2x+2y)=(x-y)(x+y)[2(x+y)²]=（x²-y²)/[2(x+y)²]

xy/(x+y)²=2xy/[2(x+y)²]