设
a
3 =
b
5 =
c
7 =
t
1 ,则
a=3t,b=5t,c=7t,
∵3a+2b-4c=9,
∴9t+10t-28t=9,
解得t=-1,
a=-3,b=-5,c=-7,
∴
1
a +
1
b +
1
c ,
=-(
1
3 +
1
5 +
1
7 ),
=-
71
105 .
设
a
3 =
b
5 =
c
7 =
t
1 ,则
a=3t,b=5t,c=7t,
∵3a+2b-4c=9,
∴9t+10t-28t=9,
解得t=-1,
a=-3,b=-5,c=-7,
∴
1
a +
1
b +
1
c ,
=-(
1
3 +
1
5 +
1
7 ),
=-
71
105 .