直角三角形已知角度和平距.求斜长和高.

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左上直角边＝49.099·tan20°5'7"＝49.099·tan20.085278°＝17.953
左下直角边＝49.099·tan5°2'48"＝49.099·tan5.046667°＝4.336
两者之和＝22.289
右上斜边＝49.099/cos20°5'7"＝49.099/cos20.085278°＝52.278
右下斜边＝49.099/cos5°2'48"＝49.099/cos5.046667°＝49.290