Question

某基坑长83米宽56米深8.5米四面放坡,边坡1:1.5.基础和地下室占体积26000立方米.预留多少回填土?余土外运,

Answer 1

V=（a+2c+kh)(b+2c+kh)h+1/3k^2h^3

=(83+1.5*8.5)(56+1.5*8.5)*8.5+1/3*1.5*1.5*8.5*8.5*8.5

=95.75*68.75*8.5+460.6

=56414.5方 56414.5*1.14=64312.53方

回填土=56414.5-26000=30414.5方 30414.5*1.05=31935.2方

余土=64312.53-31935.2=32377033方

车数=32377.33/5=6476车