Question

初二反比例函数题,要解题思路与步骤

Answer 1

顶点A,B在直线y=1.5x-7图像上

x=a,y=1.5a-7

A(a,1.5a-7)

x=a+2,y=1.5a-4

B(a+2,1.5a-4)

顶点C,D在函数y=12/x,

两底AD,BC与y轴平行,

x=a,y=12/a

D(a,12/a)

x=a+2,y=12/(a+2)

C[a+2,12/(a+2)]

AB=CD.

2^2+3^2=2^2+[12/a-12/(a+2)]^2

12/a-12/(a+2）=3或-3,

a1=-4,a2=2