已知x/y=3,求x²+2xy-3y²/x²-xy+y²
1个回答
x²+2xy-3y²/x²-xy+y²
=(x/y)²+2x/y-3/((x/y)²-x/y+1)
=(9+6-3)/(9-3+1)
=12/7
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