lim(x→1) (sin(x-1))/(x^2+x-1)的极限值,
1个回答
lim(x→1) (sin(x-1))=0
lim(x→1) (x^2+x-1)=1
所以
lim(x→1) (sin(x-1))/(x^2+x-1)=0
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