Question

y=lim (x → 0) ( √1+xsinx - √cosx) / arcsin^2x

Answer 1

y=lim (x → 0) ( √1+xsinx - √cosx) / arcsin^2x=lim (x → 0) ( 1+xsinx - cosx) / arcsin^2x( √1+xsinx +√cosx) （上下同乘以√1+xsinx +√cosx）=lim (x → 0) ( 1+xsinx - cosx) / x^2( √1+xsinx +√cosx)...