sin平方π/3+cos四次方3π/2—tan平方π/3
3个回答
(sinπ/3)^2+(cos3π/2)^4-(tanπ/3)^2
=(√3/2)^2+[cos(π+π/2)]^4-(√3)^2
=3/4+[-cosπ/2)]^4-3
=3/4+0-3
=-9/4
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