Question

线性代数矩阵两道题求解答不懂

Answer 1

1 BC=-E,BC+A =

[0 0]

[3 0]

A^2 =

[1 0]

[2*3 1]

A^n =

[1 0]

[3n 1]

(A+A^2+...+A^9) =

[9 0]

[135 9]

(A+A^2+...+A^9) (BC+A) =

[ 0 0]

[27 0]

选A.

2.A^2=E,B = A-E,

BC = (A-E)(A^10+A^9+...+A+E)

= A^11-E = A-E = B 选C.